factorise p(x) = 3x^3-5x^2-11x-3
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1
\begin{gathered}3 {x}^{3} - 5 {x}^{2} - 11x - 3 \\3 {x}^{3} - {9x}^{2} + 4 {x}^{2} - 12x + x - 3 \\ 3 {x}^{2} (x - 3) + 4x(x - 3) + 1(x - 3) \\ (x - 3)(3 {x}^{2} + 4x + 1) \\ (x - 3)(3 {x}^{2} + 3x + x + 1) \\ (x - 3)(3x(x + 1) + 1(x + 1) \\ (x - 3)(x + 1)(3x + 1)\end{gathered}
3x
3
−5x
2
−11x−3
3x
3
−9x
2
+4x
2
−12x+x−3
3x
2
(x−3)+4x(x−3)+1(x−3)
(x−3)(3x
2
+4x+1)
(x−3)(3x
2
+3x+x+1)
(x−3)(3x(x+1)+1(x+1)
(x−3)(x+1)(3x+1)
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0
Answer:
EWJKGF
Explanation:
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