Question

factorise p(x)=x^3+6x^2+11x+6​

Answer 1

bhai ye hamari |X class me nahi h

Answer 2

Answer:

USE HIDDEN TRIAL METHOD TO SOLVE IT.

Step-by-step explanation:

Using hidden trial method ,

On putting x= -2 in p(x), we get

p(-2) = (-2)^3 + 6(-2)^2 + 11(-2) + 6

p(-2) = -8 + 24 - 22 + 6

p(-2) = -30 + 30

p(-2) = 0

so, (x+2) is a factor of p(x).

Now, on dividing p(x) by x+2,we get

quotient =  x^2 + 4x + 3.

Now , factorising this quotient by splitting middle term,

= x^2 + 4x + 3

= x^2 + (3+1)x + 3

= x^2 + 3x + x + 3

= x(x + 3) + 1(x+3)

= (x+3) (x+1)

Thus , the required factors of p(x) are (x+1) , (x+2) and (x+3).

I HOPE THIS 'LL HELP YOU.