Question

factorise: p²-10p +24 ​

Answer 1

Answer:

$p {}^{2} - 10p + 24 \\ = p { }^{2} - 6p - 4p + 24 \\ = p(p - 6) - 4(p - 6)$

$= (p - 6)(p - 4)$

Answer 2

Answer:

${p}^{2} - 10p + 24 \\ \\ {p}^{2} - 6p - 4p + 24 \\ \\ p(p - 6) - 4(p - 6) \\ \\ (p - 4)(p - 6) \\ \\ take \\ \\ p - 4 = 0 \: \: \: and \: \: p - 6 = 0 \\ \\ p = 4 \: \: \: and \: \: p = 6 \\ \\ hence \: the \: value \: of \: \\ p = 4 \: and \: 6$