Question

Factorise: p2 – 10p + 25.

Answer 1

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Let see your answer !!!

$p ^{2} - 10p + 25 \\ = p ^{2} - 5p - 5p + 25 \\ = p(p - 5) - 5(p - 5) \\ = (p - 5)(p - 5)$



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Answer 2

Answer:

p²-10p+25 = (p-5)(p-5)

Explanation:

Given quadratic expression:

p²-10p+25

Method 1:

p² - 10p + 25

= p²-2×p×5 + 5²

= (p-5)²

/* By algebraic identity:

$\boxed {a^{2}-2ab+b^{2}=(a-b)^{2}}$

*/

=(p-5)(p-5)

Therefore,

p²-10p-25 = (p-5)(p-5)

Method 2:

p²-10p-25

Splitting the middle term, we get

=p²-5p-5p-25

= p(p-5)-5(p-5)

= (p-5)(p-5)

Therefore,

p²-10p+25 = (p-5)(p-5)

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