factorise: p²+p(a+1)(a+2)
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→ p² + p ( a + 1 ) ( a + 2 )
→ p² + p ( a² + 3a + 2 )
→ p² + a²p + 3ap + 2p
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0
Answer:
p² + p ( a + 1 ) ( a + 2 )
→ p² + p ( a² + 3a + 2 )
→ p² + a²p + 3ap + 2p
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