Question

factorise p³-3p²+2p-6-pq+3q
guys you say the ans as
p(3)-3p(2)+2p-6-pq+3q
3q-6p+2p-6-pq+3q
-p-6-pq+3q.
but it is wrong
the ans is
p²(p-3)+2(p-3)-q(p-3)
(p-3)(p²+2-q).
I discussed with maths professor.
I don't want to cheat others...
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Answer 1

Answer:

Yes you are right

The answer is (p - 3)(p^2 + 2 - q)

I also solved this