Question

factorise
p4 - 256​​

Answer 1

Step-by-step explanation:

p

4

=(p

2

)

2

and 256=(16)

2

Thus p

4

−256=(p

2

)

2

−(16)

2

=(p

2

−16)(p

2

+16) [∵p

2

−16=(p+4)(p−4)]

=(p+4)(p−4)(p

2

+16)

Answer 2

Step-by-step explanation:

How to solve your question

Your question is

4

−

2

5

6

p^{4}-256

p4−256

Grouping

1

Find one factor

Factor by grouping

Factor by grouping

Factor by grouping

(

−

4

)

(

3

+

4

2

+

1

6

+

6

4

)

{\color{#c92786}{({\color{#c92786}{p-4}})({\color{#c92786}{p^{3}+4p^{2}+16p+64}})}}

(p−4)(p3+4p2+16p+64)

2

Find one factor

Factor by grouping

Factor by grouping

(

−

4

)

(

+

4

)

(

2

+

1

6

)

(p-4)({\color{#c92786}{p+4}})({\color{#c92786}{p^{2}+16}})

(p−4)(p+4)(p2+16)

Solution

(

−

4

)

(

+

4

)

(

2

+

1

6

)