factorise
p4 - 256
Answers
Answered by
2
Step-by-step explanation:
p
4
=(p
2
)
2
and 256=(16)
2
Thus p
4
−256=(p
2
)
2
−(16)
2
=(p
2
−16)(p
2
+16) [∵p
2
−16=(p+4)(p−4)]
=(p+4)(p−4)(p
2
+16)
Answered by
1
Step-by-step explanation:
How to solve your question
Your question is
4
−
2
5
6
p^{4}-256
p4−256
Grouping
1
Find one factor
Factor by grouping
Factor by grouping
Factor by grouping
(
−
4
)
(
3
+
4
2
+
1
6
+
6
4
)
{\color{#c92786}{({\color{#c92786}{p-4}})({\color{#c92786}{p^{3}+4p^{2}+16p+64}})}}
(p−4)(p3+4p2+16p+64)
2
Find one factor
Factor by grouping
Factor by grouping
(
−
4
)
(
+
4
)
(
2
+
1
6
)
(p-4)({\color{#c92786}{p+4}})({\color{#c92786}{p^{2}+16}})
(p−4)(p+4)(p2+16)
Solution
(
−
4
)
(
+
4
)
(
2
+
1
6
)
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