Math, asked by maahi1079, 10 months ago

Factorise: p4 - 81q4


Anonymous: (p^2 +q^2()p+q)(p-q)

Answers

Answered by Anonymous
30

Answer:

By identity x^2 - y^2 = (x+y)(x-y)

p^4 - 81q^4 = (p^2+9q^2) (p^2 - 9q^2)

= (p^2+9q^2) (p -3q) (p+3q).

✨Hope it will help you.✨

Answered by hafizniyamatullah1
3

Answer:

(p²+9q²) (p-3q) (p+3q)

Step-by-step explanation:

p⁴-81q⁴

In this question we use identity x²-y²= (x+y) (x-y)

p⁴-81q⁴= (p²+9q²) (p²-9q²)

= (p²+9q²) (p-3q) (p+3q)

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