Factorise: p4 - 81q4
Anonymous:
(p^2 +q^2()p+q)(p-q)
Answers
Answered by
30
Answer:
By identity x^2 - y^2 = (x+y)(x-y)
p^4 - 81q^4 = (p^2+9q^2) (p^2 - 9q^2)
= (p^2+9q^2) (p -3q) (p+3q).
✨Hope it will help you.✨
Answered by
3
Answer:
(p²+9q²) (p-3q) (p+3q)
Step-by-step explanation:
p⁴-81q⁴
In this question we use identity x²-y²= (x+y) (x-y)
p⁴-81q⁴= (p²+9q²) (p²-9q²)
= (p²+9q²) (p-3q) (p+3q)
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