Question

factorise p⁴-(q+r)⁴​

Answer 1

Step-by-step explanation:

P^4 - (q+R) ^4

= (P^2)^2 - ((q +R) ^2)^2

Apply a^2 - b^2 = (a +b) (a - b)

(P^2 + (Q + R) ^2) (P^2 - (Q + R) ^2)

(P^2 + (Q + R) ^2)(P + Q + R) (P - Q - R)

Answer 2

Answer: (p^2 + q^2 + 2qr + r^)(p + q + r)(p + q - r)    

Step-by-step explanation:

$p^4 - (q + r)^4$

⇒ $(p^2)^2 - ((q + r)^2)^2$

⇒ $(p^2 - (q + r)^2)(p^2 + (q + r)^2)$            [a^2 - b^2 = (a + b)(a - b)]

⇒ $(p^2 + q^2 + 2qr + r^)(p + q + r)(p + q - r)$

[a^2 - b^2 = (a + b)(a - b)]

This is your factorisation .