Math, asked by hasnt, 1 year ago

factorise please in page plz it's important 25x^2+36y^2+49z^2+60xy-84yz-70zx

Answers

Answered by ANGEL123401
16
Hi mate your answer is...
25x^2+36y^2+49z^2+60xy+84yz+70zx
we can write above equation as..
By using formula,
(a+b+c) ^2=a^2+b^2+c^2+2ab+2bc+2ca
(5x) ^2+(6y) ^2+(7z) ^2 +( 2×5x×6y)+(2×6y×7z) +(2×7z×5x)
then this equation is written as
(5x+6y+7z) ^2
I hope it will help you....
⭐⭐⭐⭐⭐⭐⭐✨⭐⭐⭐

hasnt: means? i dont understand
ANGEL123401: check ur Q. where's sign -
hasnt: the question is to factorise 25x^2+36y^2+49z^2+60xy-84yz-70zx
ANGEL123401: +60xy+84yz+70zx in my answer
hasnt: Oooo
hasnt: then what about this one
ANGEL123401: yaa
hasnt: can you solve
ANGEL123401: i tomorrow
ANGEL123401: Hi mate your Q.solved by using identity (-a-b+c)^2
Answered by Anonymous
24
Hey there !!


▶ Question :-

→ Factorise :-

→ 25x² + 36y² + 49z² + 60xy - 84yz - 70zx .


▶ Solution :-

= 25x² + 36y² + 49z² + 60xy - 84yz - 70zx .

[ We can write this as ]

= ( 5x )² + ( 6y )² + ( -7z )² + 2 × 5x × 6y + 2 × 6y × ( -7z ) + 2 × ( -7z ) × 5x .


[ ▶Now, using Identity :-

→ a² + b² + c² + 2ab + 2bc + 2ca = ( a + b + )² .

If we put the above form on this identity is totally suitable .

Here, a = 5x ; b = 6y ; and z = -7z ]

= [ 5x + 6y + (-7z) ]² .

= ( 5x + 6y - 7z )² .

 \textit{ \bf \underline{= ( 5x + 6y - 7z ) ( 5x + 6y - 7z ) .}}



✔✔ Hence, it is solved ✅✅.


THANKS



#BeBrainly.
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