Math, asked by Rishita001, 1 year ago

Factorise please.....

 2a ^3 + 16b ^3 - 5a - 10b

Ty...☺

Answers

Answered by aaravshrivastwa
7
=>2a³+16b²-5a-10b
=>2(a³+8b²)-5(a+2b)
=>2(a+2b)(a²+4b²-2ab)-5(a+2b)
=>(a+2b)(2a²+8b²-4ab-5)


Hope it helps you.....

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Answered by Anonymous
25
 Heya \: User !!!

 Here \: Is \: The \: Solution

⤵⤵⤵

 Factorise -:

_____________________

 2a ^3 + 16b ^3 - 5a - 10b

 = 2(a ^3 + 8b ^3) - 5(a + 2b)

 = 2[(a) ^3 + (2b) ^3] - 5(a + 2b)

= 2(a + 2b) (a ^2 - 2ab + 4b ^2) - 5(a + 2b)

 Taking \: (a + 2b) \: common...

 = (a + 2b) 2(a ^2 - 2ab + 4b ^2) - 5

 = (a + 2b) (2a ^2 - 4ab + 8b ^2) - 5

 = (a - 2b) (2a ^2 - 4ab + 8b ^2 - 5)

 HOPE \: IT \: HELPS....

☺✌

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1262691: PLEASE it's my humble request to you
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Anonymous: no moree....lf u want ur solutions then ask ur question on brainly directly
aaravshrivastwa: hahahahha
1262691: ok thanku so much
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