Question

factorise..........plsss

Answer 1

$\huge\mathcal{Heya!!}$

Given equation :-

${x}^{2} + x + \frac{1}{4 }$

Taking L.C.M.

We get

$= > \frac{4 {x}^{2} + 4x + 1 }{4} = 0\\ \\ \\ = > 4 {x}^{2} + 4x + 1 = 0 \\ \\ = > 4 {x}^{2} + 2x + 2x + 1 \\ \\ = > 2x(2x + 1) + 1(2x + 1) \\ \\ = > (2x + 1)(2x + 1)$


$\huge\mathbb{Hope \ this \ helps.}$

Answer 2

Hey mate here is your answer.

Please refer to the attachment.

Hope this answer helps you mate.

Please mark me as the brainliest one.

Thank you.