Question

Factorise( plz add explanation if you can)
(2x-3)^2-(3x-2)^2​

Answer 1

Answer:x=1

Step-by-step explanation:

$(2x-3)^{2}$-$(3x-2)^{2}$=0   First simply solve this equation by the formula $(a-b)^{2}$

=>$4x^{2}$-12x+9-($9x^{2}$-12x+4)=0

=>$4x^{2}$-12x+9-$9x^{2}$+12x-4=0

=>-$5x^{2}$+5=0

=>$5x^{2}$-5=0

=>$5x^{2}$=5

=>$x^{2}$=5/5=1  

=>x=$\sqrt{1}$=1