Factorise:
Plz solve it fast, I have my exam a day after ..
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Step-by-step explanation:
Given that,
2 ( pq + rs ) - p² - q² + r² + s²
= 2pq + 2rs - p² - q² + r² + s²
= r² + s² + 2rs - p² - q² + 2pq
= ( r + s )² - ( p² + q² - 2pq ) ( ∵ " - " common )
= ( r + s )² - ( p - q )² is the answer. [∵(a+b² = a²+b²+2ab, (a-b)²= a²+ b²- 2ab ]
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