Question

factorise plzzzz................ ...
bx²- ax + b

Answer 1

=> bx² - ax + b _______[GIVEN]

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USING FACTORISE FORNULA :-

$= > x = \frac{ - b \binom{ + }{ - } \sqrt{ {b}^{2} - 4ac } }{2a}$
HERE

=> a= b, b = -a, c=b

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PUT THE VALUE IS FACTORISE FORMULA :-

$= > x = \frac{ - b \binom{ + }{ - } \sqrt{ {b}^{2} - 4ac } }{2a} \\ \\ = > x = \frac{ - ( - a) \binom{ + }{ - } \sqrt{ {( - a)}^{2} - 4 \times b \times b} }{2b} \\ \\ = > x = \frac{a \binom{ + }{ - } \sqrt{ {a}^{2} - 4 {b}^{2} } }{2b} \\ \\ = > x = \frac{a \binom{ + }{ - } \sqrt{ {a}^{2} - {(2b)}^{2} } }{2b} \\ \\ = > x = \frac{a \binom{ + }{ - } \sqrt{(a + 2b)(a - 2b)} }{2b} \\ \\ = > x = \frac{a + \sqrt{(a + 2b)(a - 2b)} }{2b} \\ \\ AND \\ \\ = > x = \frac{a - \sqrt{(a + 2b)(a - 2b)} }{2b}$
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THEN

$= > b {x}^{2} - ax + b = 0 \\ \\ = > (x - \frac{a + \sqrt{(a + 2b)(a - 2b)} }{2b} ).(x - \frac{a + \sqrt{(a + 2b)(a - 2b)} }{2b} ) = 0$
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