Question

Factorise : pq²+q(p-1)-1=?​

Answer 1

Answer:

(pq - 1)(q + 1)

Step-by-step explanation:

Aim: To factorise the given expression.

$pq^2 + q (p - 1) - 1$

$= pq^2 + qp - q - 1$

$= (pq^2 + qp) + (-q - 1)$

$= pq(q + 1) - 1(q + 1)$

$= (pq - 1)(q + 1)$

Therefore, the solution is (pq - 1)(q + 1).

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Answer 2

EXPLANATION.

Factorizes :

⇒ pq² + q(p - 1) - 1.

As we know that,

⇒ pq² + qp - q - 1.

⇒ pq(q + 1) - 1(q + 1).

⇒ (pq - 1)(q + 1).

                                                                                                                     

MORE INFORMATION.

(1) = (x + y)² = x² + y² + 2xy.

(2) = (x - y)² = x² + y² - 2xy.

(3) = (x² + y²) = (x + y)² - 2xy.

(4) = (x² - y²) = (x + y)(x - y).

(5) = (x + y)³ = x³ + 3x²y + 3xy² + y³.

(6) = (x - y)³ = x³ - 3x²y + 3xy² - y³.

(7) = (x³ + y³) = (x + y)(x² - xy + y²).

(8) = (x³ - y³) = (x - y)(x² + xy + y²).