Math, asked by gamingforpubgwithadi, 9 months ago

factorise pq⁴-p(p-q)⁴​

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Answered by mdyasinashrafi10786
4

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Answered by UtsavPlayz
6

p {q}^{4}  - p(p - q) ^{4}  \\ =  p( {q}^{4}  - (p - q) ^{4} ) \\  = p( {q}^{2}  + (p - q) ^{2} )( {q}^{2}  - (p - q) ^{2}  )\\  = p( {q}^{2}  +  {p}^{2}  +  {q}^{2}  - 2pq)(q + p - q)(q - p + q) \\  = p(2 {q}^{2}  +  {p}^{2}  - 2pq)(p)(2q - p) \\  =  {p}^{2} (2 {q}^{2}  +  {p}^{2}  - 2pq)(2q - p)

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