factorise psquare - 3pq+ 2qsquare
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Answered by
7
Hey
here's your answer !!
p^2 - 3pq + 2 q^2
= p^2 - 2pq - pq + 2 q^2
= p ( p - 2q ) - q ( p - 2q )
= ( p - q ) ( p - 2q ) . [ ANSWER ]
Hope it helps !!
here's your answer !!
p^2 - 3pq + 2 q^2
= p^2 - 2pq - pq + 2 q^2
= p ( p - 2q ) - q ( p - 2q )
= ( p - q ) ( p - 2q ) . [ ANSWER ]
Hope it helps !!
Incredible29:
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Answered by
3
p^2-3pq+2q^2=>p^2-2pq-pq+2q^2
=>p(p-2q)-q(p-2q)
=>(p-q)(p-2q)
therefore,factorization of p^2-3pq+2q^2 is
=>(p-q)(p-2q)
=>p(p-2q)-q(p-2q)
=>(p-q)(p-2q)
therefore,factorization of p^2-3pq+2q^2 is
=>(p-q)(p-2q)
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