factorise q^2+6q-16
Answers
Answer:
1.1 Factoring q2-6q-16
The first term is, q2 its coefficient is 1 .
The middle term is, -6q its coefficient is -6 .
The last term, "the constant", is -16
Step-1 : Multiply the coefficient of the first term by the constant 1 • -16 = -16
Step-2 : Find two factors of -16 whose sum equals the coefficient of the middle term, which is -6 .
-16 + 1 = -15
-8 + 2 = -6 That's it
Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -8 and 2
q2 - 8q + 2q - 16
Step-4 : Add up the first 2 terms, pulling out like factors :
q • (q-8)
Add up the last 2 terms, pulling out common factors :
2 • (q-8)
Step-5 : Add up the four terms of step 4 :
(q+2) • (q-8)
Which is the desired factorization
Answer:
The first term is, q2 its coefficient is 1 .
The middle term is, +6q its coefficient is 6 .
The last term, "the constant", is -16
Step-1 : Multiply the coefficient of the first term by the constant 1 • -16 = -16
Step-2 : Find two factors of -16 whose sum equals the coefficient of the middle term, which is 6 .
-16 + 1 = -15
-8 + 2 = -6
-4 + 4 = 0
-2 + 8 = 6 That's it
Step-by-step explanation:
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