Question

Factorise quadratic expressions j^2+4jk+4k^2

Answer 1

Answer:

(j+2k)*(j+2k)

Step-by-step explanation:

j^2+4jk+4k^2

=(j)^2+2*j*2k+(2k)^2

[Since, a^2+2ab+b^2=(a+b)^2]

=(j+2k)^2

=(j+2k)*(j+2k). (Answer)