Question

Factorise question.6

Answer 1

Answer:

this is of the form

${(a + b + c)}^{2} = {a}^{2} + {b}^{2} + {c}^{2} + 2ab + 2bc + 2ac \\ therefore \: to \: solve \: it \: just \: take \: the \: of \: the \: first \: 3 \: terms \\ = \sqrt{16{x}^{2} } + \sqrt{ 4{y}^{2} } + \sqrt{ {9z}^{2} } \\ = {(4x + 2y + 3z)}^{2}$

this is the answer pls mark as brainliest answer and like it thank u !!

Answer 2

Answer:

16x² + 4y² + 9z² - 16xy - 12yz +24zx

= (4x)² + (-2y)² + (3z)² + 2(4x)(-2y) + 2(-2y)(3z) + 2(4x)(3z)

= (4x - 2y + 3z)²

= (4x - 2y + 3z)(4x - 2y + 3z)