Question

factorise rhw following expression 4a²+4-8a​

Answer 1

$we \: know \: the \: algebraic \: identify \\ {x}^{2} + y {}^{2} + {z}^{2} + 2xy + 2yz + 2zx = (x + y + z) {}^{2} \\ now \\ 4a {}^{2} + b {}^{2} + 4ab + 8a + 4b + 4 \\ = 4a { }^{2} + b {}^{2} + 4 + 4ab + 4b + 8a \\ = (2a {}) {}^{2} + b {}^{2} + 2 {}^{2} + 2 \times 2a \times b +2 \times b \times 2 + 2 \times 2 \times 2a \\ = (2a + b + 2) {}^{2} \\ = (2a + b + 2)(2a + b + 2) \\ .......$

sorry wrong Answer plz report this