Question

factorise root 2x2 + 3x + root 2

Answer 1

ANSWER:

$(x=-\sqrt{2}),\left(x=-\frac{1}{\sqrt{2}}\right)$

SOLUTION:

Using quadratic equation, we find the root of the equation $\sqrt{2} x^{2}+3 x+\sqrt{2}$

First, we divide the value of 3 into 2 and after that the equation will look like this

$\sqrt{2} \mathrm{x}^{2}+2 \mathrm{x}+\mathrm{x}+\sqrt{2}$

The 2 as common for the first part and 1 for the second part we get

$\sqrt{2} \mathrm{x}(\mathrm{x}+\sqrt{2})+1(\mathrm{x}+\sqrt{2})$

Therefore, joining the roots, we get

$(x+\sqrt{2})(\sqrt{2} x+1)$

Hence the value of is either, $(x=-\sqrt{2}),\left(x=-\frac{1}{\sqrt{2}}\right)$.