Question

factorise root under 2 x square plus 3x plus root under Tu plz solve this ​

Answer 1

$2 {x}^{2} + 3x + \sqrt{2}$

$= 2 {x }^{2} + 2x \sqrt{2} + 1x \sqrt{1} + \sqrt{2}$

$2x(x + \sqrt{2} ) + \sqrt{1} (x + \sqrt{2})$

$= (2x + \sqrt{1} ) \: (x + \sqrt{2})$

$hope \: it \: helps$