Factorise see the attachment Help me
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Solution :-
→ ( 2a - b + c )²
→ ( 2a )² + b² + c² + 2 [ 2a × ( - b ) + ( - b ) × c + 2a × c ]
→ 4a² + b² + c² + 2 [ - 2ab - bc + 2ac ]
→ 4a² + b² + c² - 4ab - 2bc + 4ac
IdentitY Used :-
→ ( a + b + c )² = a² + b² + c² + 2 ( ab + bc + ac )
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