Question

factorise sinA.cos2A+sin2A.cosA​

Answer 1

Answer:

Step-by-step explanation:

==> cos 2A - cos A = sin A - sin 2A

==> -2 sin 3A/2 sin A/2 = -2 cos 3A/2 sin A/2 {since - ve sign comes out of sine}

Cancelling -2 and sin A/2 we have

tan 3A/2 = 1

==> tan 3A/2 = tan π/4

===> 3A/2 = nπ + π/4

==> A = 2/3 *(nπ + π/4)

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Answer 2

Answer:

sinA.cos2A+sin2A.cosA is in the form of

sinA.cosB+cosA.sinB=sin(A+B)

sinA.cos2A+sin2A.cosA=sin(A+2A)