factorise step by step 25a^2-4b+28bc-49c^2
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(5a)^2 - [(2b)^2 - (2)(7)(bc)+(7c)^2] {I took minus sign out of the bracket.}
(5a)^2 - (2b- 7c)^2
By a^2-b^2 identity,
(5a+2b-7c)(5a-2b+7c)
PLEASE FEEL FREE TO ASK IF YOU DIDN'T UNDERSTAND ANY STEP.
(5a)^2 - (2b- 7c)^2
By a^2-b^2 identity,
(5a+2b-7c)(5a-2b+7c)
PLEASE FEEL FREE TO ASK IF YOU DIDN'T UNDERSTAND ANY STEP.
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