Question

factorise t^2+23t-108​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Hey friend,

Here is the solution :-

${t}^{2} - 23t - 108 = 0 \\ \\ {t}^{2} - 27t + 4t - 108 = 0 \\ \\ t(t - 27) + 4(t - 27) = 0 \\ \\ (t - 27)(t + 4) = 0 \\ \\ t - .27 = 0 \\ t = 27 \\ \\ t + 4 = 0 \\ t = - 4$

$here \: we \: get \: two \: values \: of \\ t = 27 \: and \: - 4$

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