Math, asked by shashwat24339, 1 year ago

Factorise t^2+2pt-35p^2​

Answers

Answered by Anonymous
29

 {t}^{2}  + 2pt \:  - 35p {}^{2}  \\  \\ factorise \: by \: spilitng \: the \: mid \: value \\  \\  7 - 5 = 2 \\  7 \times 5 = 35 \\  \\  {t}^{2}   + (7 - 5)pt \:  -  35 {p}^{2}  \\  \\   {t}^{2} + 7pt - 5pt - 35 {p}^{2}   \\  \\ t(t + 7p) - 5p(t + 7p) \\  \\ (t - 5p)(t + 7p)

Answered by Angel9894
0

Step-by-step explanation:

t^2+2pt -35p^2

t^2 -5pt +7pt-35p^2

t (t-5p) +7p (t-5p)

(t-5p) (t+7p) =0

put ÷

t -5p =0

t =5p

or

t+7p=0

t= -7p

Nwgative valve is neglect so answer is t = 5p

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