Factorise : t (square) +23t -108
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Answered by
10
t² + 27t -4t -108
= t(t+27)-4(t+27)
= (t-4)(t+27)
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= t(t+27)-4(t+27)
= (t-4)(t+27)
HOPE IT HELPS!
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Answered by
10
t^2+23t-108
=t^2-4t+27t-108
=t (t-4)+27 (t-4)
=(t+27)(t-4)
=t^2-4t+27t-108
=t (t-4)+27 (t-4)
=(t+27)(t-4)
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