Question

factorise
$(16x^{2} \div 9) - (4y^{2} \div 25)$
​

Answer 1

Answer:

$\frac{16x {}^{2} }{9} - \frac{4y {}^{2} }{25} \\ \\ = ( \frac{4x}{3} ) {}^{2} - ( \frac{2y}{5} ) {}^{2} \\ \\ = ( \frac{4x}{3} + \frac{2y}{5} )( \frac{4x}{3} - \frac{2y}{5} ) \\ \\ \\ formula \: \: - \: \: (x {}^{2} - y {}^{2} ) = (x + y)(x - y)$