Question

Factorise :
$16x ^{2} - y ^{2} + 4yz - 4 {z}^{2}$
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Answer 1

Answer:

$16x {}^{2} - y {}^{2} + 4yz - 4 {z}^{2} \\ {(4x)}^{2} - ( {y}^{2} - 2(y)(2z) + {(2z)}^{2} ) \\ {(4x)}^{2} - ( {y - 2z) }^{2} \\ (4x - y + 2z)(4x - + y - 2z)$