Math, asked by chaudharymeenu9, 11 months ago

factorise:-
2 \sqrt{2} x ^{2}  + 11x + 6 \sqrt{2}

Answers

Answered by Anonymous
2

Step-by-step explanation:

2  \sqrt{2}  {x}^{2}  + 11x + 6 \sqrt{2}  \\  \\ 2 \sqrt{2}  {x}^{2}  + 8x + 3x + 6  \sqrt{2}   \\  \\ (2 \sqrt{2}  {x}^{2}  + 8x) + (3x + 6 \sqrt{2} ) \\  \\ 2 \sqrt{2} x( x + 2 \sqrt{2} ) + 3(x + 2 \sqrt{2} ) \\  \\ (2 \sqrt{2}x  + 3)(x + 2 \sqrt{2} )  = 0\\  \\ 2 \sqrt{2} x + 3 = 0 \: or \: x + 2 \sqrt{2}  = 0 \\  \\ 2 \sqrt{2} x =  - 3 \: or \: x =  - 2 \sqrt{2}  \\  \\  x =  \frac{ - 3}{2 \sqrt{2} }  \: or \:  x =  - 2 \sqrt{2}

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