Math, asked by srishtij032, 10 months ago

Factorise
$2 \sqrt{2} {x}^{2} + 4x + \sqrt{2}$

2√2x^2 + 4x + √2

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Answered by Anonymous

1

Answer:

2√2x^2 + 4x + √2

=2√2x^2 +2x+2x + √2

=2x(√2x + 2) + √2(√2x + 2)

=x=-2/√2

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Answered by Anonymous

1

Answer:

refer with the attachment.......

hope it helps......

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