Factorise :-
Answers
Answered by
0
Answer:
3.4028237e+38
Step-by-step explanation:
Answered by
27
Answer:
256x^{16} - 1 = (16x^8+1)(4x^4+1)(2x^2+1)(2x^2-1)256x
16
−1=(16x
8
+1)(4x
4
+1)(2x
2
+1)(2x
2
−1)
Step-by-step explanation:
Given : 256x^{16} - 1256x
16
−1
To Find : Factorize
Solution:
256x^{16}-1256x
16
−1
16x^8)^2-1^216x
8
)
2
−1
2
(16x^8+1)(16x^8-1)(16x
8
+1)(16x
8
−1)
(16x^8+1)[(4x^4)^2-1^2)](16x
8
+1)[(4x
4
)
2
−1
2
)]
(16x^8+1)(4x^4+1)(4x^4-1)(16x
8
+1)(4x
4
+1)(4x
4
−1)
(16x^8+1)(4x^4+1)[(2x^2)^2-1^2](16x
8
+1)(4x
4
+1)[(2x
2
)
2
−1
2
]
(16x^8+1)(4x^4+1)(2x^2+1)(2x^2-1)(16x
8
+1)(4x
4
+1)(2x
2
+1)(2x
2
−1)
Hence 256x^{16} - 1 = (16x^8+1)(4x^4+1)(2x^2+1)(2x^2-1)256x
16
−1=(16x
8
+1)(4x
4
+1)(2x
2
+1)(2x
2
−1)
Similar questions