Question

factorise
$27 {x}^{3 } + {y}^{3} + {z}^{3} - 9xyz$
​

Answer 1

Answer:

27x

3

+y

3

+z

3

−9xyz

=(3x)

3

+y

3

+z

3

−9xyz

=(3x)

3

+y

3

+z

3

−3×3x×y×z

using identity

a

3

+b

3

+c

3

−3abc=(a+b+c)(a

2

+b

2

+c

2

−ab−bc−ca)

Putting a=3x,b=y,c=z

=(3x+y+z)(9x

2

+y

2

+z

2

−3xy−yz−3zx).

Answer 2

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I f you are bad then I am your dad from Maari 2