Question

factorise-
${2a}^{2} {b}^{2} + ab - 45$
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Answer 1

$\red{\large {\underline{ \underline{ \star \: {Given:-}}}}}$

$Factorise \: \: \: \: \: \: </p><p>{2a}^{2} {b}^{2} + ab - 45.$

$\red{\large {\underline{ \underline{ \star \: {Solution:-}}}}}$

$2 {a}^{2} {b}^{2} + ab - 45. \\ \\ \implies 2 {a}^{2} {b}^{2} + 10ab - 9ab - 45. \\ \\ \implies 2ab(ab + 5) - 9(ab + 5). \\ \\ \implies (2ab - 9)(ab + 5). \\ \\ \implies ab = \frac{9}{2} \: \: \: \: \: \: and \: \: \: \: \: \: - 5.$