factorise
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2(a+3b)-3(a+3b)²
= (a+3b)[2-3(a+3b)]
= (a+3b)(2-3a-9b)
It is the answer
any doubts comment ;))
= (a+3b)[2-3(a+3b)]
= (a+3b)(2-3a-9b)
It is the answer
any doubts comment ;))
Swarup1998:
Nice answer... keep it up
Answered by
1
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