Math, asked by Flash1111, 1 year ago

Factorise
2x {}^{3}  - x {}^{2}  - 13x - 6

Answers

Answered by sumit3351
1
it is factorise by factor therome
Answered by JinKazama1
0
Final Answer : (x+2)(x-3)(2x+1)
Steps:
1)
Let f(x) =
2 {x}^{3} - {x}^{2} - 13x - 6
By inspection,
f(-2) = 2(-2)^3 -(-2)^2 -13(-2) - 6
= -16-4+26-6 = 0
By Factor Theorem,
(x+2) is factor of f(x).

2) So, we divide f(x) by (x+2) as shown in pic.

We get quotient as
2 {x}^{2} - 5x - 3
3) Now,
2 {x}^{2} - 5x - 3 = \\ 2 {x}^{2} - 6x + x - 3 \\ = > 2x(x - 3) + 1(x - 3) \\ = > (2x + 1)(x - 3)

Therefore,
Factorisation is
(x+2)(2x+1)(x-3)
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