factorise
![(2x + \frac{1}{3} ) {}^{2} - (x - \frac{1}{2} ) {}^{2} (2x + \frac{1}{3} ) {}^{2} - (x - \frac{1}{2} ) {}^{2}](https://tex.z-dn.net/?f=%282x++%2B++%5Cfrac%7B1%7D%7B3%7D+%29+%7B%7D%5E%7B2%7D++-+%28x+-++%5Cfrac%7B1%7D%7B2%7D+%29+%7B%7D%5E%7B2%7D+)
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2x +2 = 0. Step-by- step explanation: root 2x square = 2x. so the question will become. 2x - 2x + 1- 2x + 3 =0.
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