Math, asked by pratibhapatil73031, 2 months ago

factorise

 = 2y {}^{2}  - 11y + 5

Answers

Answered by BrainlysCrazyBoy
11

\huge\fbox{QUESTIONσ}

2y^{2}  - 11y + 5

\huge\fbox{ANSWER߷}

2y ^{2}  - 11y + 5 \\  \\  = 2y^{2}   - 10y  + 1y + 5 \\ \fbox\textbf{mid \: term \: theorem} \\  \\  = 2y(y - 5) - 1(y - 5) \\  \\  = (2y - 1)(y - 5)

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