Question

factorise
$3(x + 2 {)}^{2} - 5(x + 2) + 2$
​

Answer 1

Answer:

$= > 3{(x )}^{2} - 2(x)(2) + (2 {)}^{2} - 5x - 8 - 2$

$= > 3( {x - 4x + 4} ) - 5x - 8 - 2$

$= > 3 {x}^{2} - 12x + 12 - 5x - 8 - 2$

$= > 3 {x}^{2} - 17x + 12 - 8 - 2$

$= > 3 {x}^{2} - 17x + 4 - 2$

$= > 3 {x}^{2} - 17x + 2$

HOPE THIS HEIPS U.......

Answer 2

Answer:

$\huge\bold\red{ANSWER}$

Step-by-step explanation:

$\large{\underline{\rm{\red{SOLUTION :}}}}$

$\implies \sf \blue {Let\:us\:assume\:x+2\:as\:x}\\ \implies \sf \pink {3x^2-5x+2=0} \\ \implies \sf \pink {3x^2-3x-2x+2=0}\\ \implies \sf \pink {3x(x-1)-2(x-1)=0}\\ \implies \sf \pink {(3x-2)(x-1)=0}\\ \implies \sf \pink {x=\frac{2}{3},1}$

case 1:

$\implies \sf \pink {x+2=\frac{2}{3}}\\ \implies \sf \pink {x=\frac{-4}{3}}$

case 2:

$\implies \sf \blue {x+2=1}\\ \implies \sf \blue {x=-1}$

$\sf {The\: factorisation\:is\:in\:first\:para,if\:you\:want\:x\:value\:see\:2nd\:and\:3rd\:para$