Question

factorise
$3 {x}^{2} - 2 \sqrt{6} x + 2 = 0$
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Answer 1

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Q:-factorise

$3 {x}^{2} - 2 \sqrt{6} x + 2 = 0$

$\huge\tt\underline\blue{ANSWER }$

------>>>>Here is your answer<<<<--------

$➪ 3 {x}^{2} - 2 \sqrt{6} x + 2 = 0$

$➪3 {x}^{2} - \sqrt{6} x - \sqrt{6} x + 2 = 0$

$➪ \sqrt{3} x( \sqrt{3} x - \sqrt{2} ) - \sqrt{2} ( \sqrt{3} x - \sqrt{2} )$

$➪( \sqrt{3} x - \sqrt{2} )( \sqrt{3} x - \sqrt{2} )$

$➪ \sqrt{3} x - \sqrt{2} = 0$

$➪ \sqrt{3} x - \sqrt{2} = 0$

$➪x = \sqrt{ \frac{2}{3} } ✓$

$➪x = \sqrt{ \frac{2}{3} } ✓$

HOPE IT HELPS YOU..

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Answer 2

$\bf \huge{ \underline{ \underline{ \blue{Answer : }}}} \\ \\ \sf \mapsto \: {3x}^{2} - 2 \sqrt{6} x + 2 = 0 \\ \\ \sf \mapsto \: {3x}^{2} - \sqrt{6} x - \sqrt{6} x + 2 = 0 \\ \\\sf \mapsto \: \sqrt{3} x( \sqrt{3} x - \sqrt{2} ) - \sqrt{2} ( \sqrt{3} x - \sqrt{2} ) = 0 \\ \\ \sf \mapsto \: ( \sqrt{3} x - \sqrt{2} )( \sqrt{3} x - \sqrt{2} ) = 0 \\ \\ \sf \mapsto \: x = \frac{ \sqrt{2} }{ \sqrt{3} } \\ \\ \tt \blue{ \therefore \: \: \: the \: \: equation \: \: has \: \: 2 \: \: equal \: \: roots \: \: : - \: \: \: \: \: \: \: \frac{ \sqrt{2} }{ \sqrt{3} } }$