Question

factorise
${3u}^{3} + {4u}^{2} - 12u + 16$

Answer 1

Heya !!




3U³ + 4U² - 12U - 16



U² ( 3U + 4 ) - 4 ( 3U + 4 )


( 3U + 4 ) ( U²-4 ) = 0




( 3U + 4 ) = 0 OR ( U² - 4 ) = 0



U = -4/3 OR U = 2.