Question

factorise

$3x {}^{2} - 2x - 8$
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Answer 1

3x^2-2x-8

3x^2-6x+4x-8

3x(x-2)+4(x-2)

(x-2)(3x+4)

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Answer 2

Answer:

$3 {x}^{2} - 2x - 8 \\ 3 {x}^{2} - 6x + 4x - 8 \\ \\ 3x(x - 2) + 4(x - 2) \\ \\ (3x + 4)(x - 2)$