Question

factorise :

$3x ^{2} - x - 4$
​

Answer 1

Step-by-step explanation:

3x^2-x-4=0

3x^2+3x-4x-4=0

3x(x+1)-4(x+1)=0

(3x-4)(x+1)=0

Mark as brilliant and take thanks for all question

Answer 2

Solution

$\bold{ {3x}^{2} - x - 4}$

$= > {3x}^{2} + 3x - 4x - 4$

$= > 3x(x + 1) - 4(x + 1)$

$= > (3x - 4)(x + 1)$

✨ Additional information ✨

______________________________________

$(x + y) ^{2} = {x}^{2} + {y}^{2} + 2xy$

_______________________________________

$(x - y) ^{2} = {x}^{2} + {y}^{2} - 2xy$

_______________________________________

${x}^{2} - {y}^{2} = (x + y)(x - y)$

_______________________________________

$(x + a)(x + b) = {x}^{2} + (a + b)x + ab$

______________________________________