Question

factorise
$48 {x}^{3} - 27x$

Answer 1

Hey user

Here is your answer :-

_______________________________

48x^3 - 27x

= 3x ( 16x^2 - 9 )

= 3x [ ( 4x )^2 - ( 3 )^2 ]

= 3x ( 4x - 3 )( 4x + 3 )

Since a^2 - b^2 = ( a + b )( a - b )

Answer 2

Answer:

Step-by-step explanation:

Hey user

Here is your answer :-

_______________________________

48x^3 - 27x

= 3x ( 16x^2 - 9 )

= 3x [ ( 4x )^2 - ( 3 )^2 ]

= 3x ( 4x - 3 )( 4x + 3 )

Since a^2 - b^2 = ( a + b )( a - b )