Math, asked by Anonymous, 5 months ago

Factorise

 5 {m}^{2}  - 5 {n}^{2}

Answers

Answered by unknownperson16
1

5m²-5n²

using (a²-b²)=(a+b)(a-b)

(√5m+√5n)(√5m-√5n)

hence the two factors are-

(√5m+√5n) & (√5m-√5n)

hope it helps you

Answered by Anonymous
2

{\fbox{\fbox{\fbox{\fbox{\fbox{\fbox{\fbox{\fbox{\fbox{\fbox{\fbox{\fbox{\fbox{\fbox{\fbox{\fbox{\fbox{\fbox{\fbox{\fbox{\fbox{\fbox{\fbox{\fbox{\fbox{Answer}}}}}}}}}}}}}}}}}}}}}}}}}}

 ✯ \: \sf 5 {m}^{2} - 5 {n}^{2}

 ☞ \: \sf 5 ({m}^{2} - {n}^{2})

By using identinty a²-b²=(a+b)(a-b)

 ☞ \: \sf 5 ({m}^{2} - {n}^{2}) =5 (m+n)(m-n)

 \boxed{\sf 5 (m+n)(m-n)}

Therefore, answer is 5(m+n)(m-n)

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