Question

factorise
${64a}^{3} - {27b}^{3} - {144a}^{2}b + 108a{b}^{2}$

Answer 1

HELLO DEAR,

64a³ - 27b³ - 144a²b + 108ab²

=> (4a)³ - (3b)³ - 36ab(4a-3b)

Now,

We know that:-

(a-b)² = a³ - b³ - ab(a-b)

Hence,

(4a-3b)³ = 64a³ - 27b³ - 144a²b + 108ab²


I HOPE ITS HELP YOU DEAR,
THANKS

Answer 2

Heya user
Here is your answer !!

64a^3 - 27b^3 - 144a^2b + 108ab^2
= (4a)^3 - (3b)^3 - 3(4a)^2×3b + 3(3b)^2×4a
= ( 4a - 3b )^3 [ Ans ]

Hope it helps !!