Question

Factorise
$6ab - b {2}^{2} + 12ac - 2bc$
​

Answer 1

Step-by-step explanation:

6ab - b² + 12ac - 2bc

= 6ab + 12ac - b² - 2bc

= 6a (b + 2c ) - b ( b + 2c )

= ( b+ 2c ) ( 6a - b )